Y=(3X-4)(5X+1/2X+7)

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Solution for Y=(3X-4)(5X+1/2X+7) equation: 


x in (-oo:+oo)

Y = (3*X-4)*(5*X+(1/2)*X+7) // - (3*X-4)*(5*X+(1/2)*X+7)

Y-((3*X-4)*(5*X+(1/2)*X+7)) = 0

Y-1*(3*X-4)*(11/2*X+7) = 0

Y-1*(3*X-4)*(11/2*X+7) = 0

X-33/2*X^2+Y+28 = 0

X-33/2*X^2+Y+28 = 0

x belongs to the empty set

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