Y=(7x-14)(9x+18)

Solution for Y=(7x-14)(9x+18) equation:

=(7Y-14)(9Y+18)

We move all terms to the left:

-((7Y-14)(9Y+18))=0

We multiply parentheses ..

-((+63Y^2+126Y-126Y-252))=0


We calculate terms in parentheses: -((+63Y^2+126Y-126Y-252)), so:

(+63Y^2+126Y-126Y-252)

We get rid of parentheses

63Y^2+126Y-126Y-252

We add all the numbers together, and all the variables

63Y^2-252

Back to the equation:

-(63Y^2-252)


We get rid of parentheses

-63Y^2+252=0

a = -63; b = 0; c = +252;
Δ = b2-4ac
Δ = 02-4·(-63)·252
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{63504}=252$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-252}{2*-63}=\frac{-252}{-126}
=+2
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+252}{2*-63}=\frac{252}{-126}
=-2
$