Y=-0.25x(x-48)

Solution for Y=-0.25x(x-48) equation:

=-0.25Y(Y-48)

We move all terms to the left:

-(-0.25Y(Y-48))=0


We calculate terms in parentheses: -(-0.25Y(Y-48)), so:

-0.25Y(Y-48)

We multiply parentheses

-0Y^2-0Y

We add all the numbers together, and all the variables

-1Y^2-1Y

Back to the equation:

-(-1Y^2-1Y)


We get rid of parentheses

1Y^2+1Y=0

We add all the numbers together, and all the variables

Y^2+Y=0

a = 1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*1}=\frac{-2}{2}
=-1
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*1}=\frac{0}{2}
=0
$