Y=-0.5(x+0)(x-8)

Solution for Y=-0.5(x+0)(x-8) equation:

=-0.5(Y+0)(Y-8)

We move all terms to the left:

-(-0.5(Y+0)(Y-8))=0

We add all the numbers together, and all the variables

-(-0.5(+Y)(Y-8))=0

We multiply parentheses ..

-(-0.5(+Y^2-8Y))=0


We calculate terms in parentheses: -(-0.5(+Y^2-8Y)), so:

-0.5(+Y^2-8Y)

We multiply parentheses

-0.5Y^2+4Y

Back to the equation:

-(-0.5Y^2+4Y)


We get rid of parentheses

0.5Y^2-4Y=0

a = 0.5; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·0.5·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*0.5}=\frac{0}{1}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*0.5}=\frac{8}{1}
=8
$