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=-1/3(Y-5)(Y-5)
We move all terms to the left:
-(-1/3(Y-5)(Y-5))=0
Domain of the equation: 3(Y-5)(Y-5))!=0We multiply parentheses ..
Y∈R
-(-1/3(+Y^2-5Y-5Y+25))=0
We multiply all the terms by the denominator
-(-1=0
We add all the numbers together, and all the variables
=0
Y=0/1
Y=0
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