Y=-16x2+50x+7

Solution for Y=-16x2+50x+7 equation:

=-16Y^2+50Y+7

We move all terms to the left:

-(-16Y^2+50Y+7)=0

We get rid of parentheses

16Y^2-50Y-7=0

a = 16; b = -50; c = -7;
Δ = b2-4ac
Δ = -502-4·16·(-7)
Δ = 2948
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2948}=\sqrt{4*737}=\sqrt{4}*\sqrt{737}=2\sqrt{737}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{737}}{2*16}=\frac{50-2\sqrt{737}}{32}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{737}}{2*16}=\frac{50+2\sqrt{737}}{32}
$