Y=-2(x-8)(x+4)

Solution for Y=-2(x-8)(x+4) equation:

=-2(Y-8)(Y+4)

We move all terms to the left:

-(-2(Y-8)(Y+4))=0

We multiply parentheses ..

-(-2(+Y^2+4Y-8Y-32))=0


We calculate terms in parentheses: -(-2(+Y^2+4Y-8Y-32)), so:

-2(+Y^2+4Y-8Y-32)

We multiply parentheses

-2Y^2-8Y+16Y+64

We add all the numbers together, and all the variables

-2Y^2+8Y+64

Back to the equation:

-(-2Y^2+8Y+64)


We get rid of parentheses

2Y^2-8Y-64=0

a = 2; b = -8; c = -64;
Δ = b2-4ac
Δ = -82-4·2·(-64)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24}{2*2}=\frac{-16}{4}
=-4
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24}{2*2}=\frac{32}{4}
=8
$