Y=-2x2+8x-8

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Solution for Y=-2x2+8x-8 equation: 



=-2Y^2+8Y-8

We move all terms to the left:

-(-2Y^2+8Y-8)=0

We get rid of parentheses

2Y^2-8Y+8=0

a = 2; b = -8; c = +8;
Δ = b2-4ac
Δ = -82-4·2·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{8}{4}=2$

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