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=-2Y^2-3Y-2
We move all terms to the left:
-(-2Y^2-3Y-2)=0
We get rid of parentheses
2Y^2+3Y+2=0
a = 2; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·2·2
Δ = -7
Delta is less than zero, so there is no solution for the equation
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