Y=-3(x+2)(x-2

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Solution for Y=-3(x+2)(x-2 equation:



=-3(Y+2)(Y-2
We move all terms to the left:
-(-3(Y+2)(Y-2)=0
We use the square of the difference formula
Y^2+4=0
a = 1; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·1·4
Δ = -16
Delta is less than zero, so there is no solution for the equation

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