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=-3Y^2+30Y-75
We move all terms to the left:
-(-3Y^2+30Y-75)=0
We get rid of parentheses
3Y^2-30Y+75=0
a = 3; b = -30; c = +75;
Δ = b2-4ac
Δ = -302-4·3·75
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$Y=\frac{-b}{2a}=\frac{30}{6}=5$
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