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=-5Y(2)+30Y-25
We move all terms to the left:
-(-5Y(2)+30Y-25)=0
We add all the numbers together, and all the variables
-(-5Y^2+30Y-25)=0
We get rid of parentheses
5Y^2-30Y+25=0
a = 5; b = -30; c = +25;
Δ = b2-4ac
Δ = -302-4·5·25
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-20}{2*5}=\frac{10}{10} =1 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+20}{2*5}=\frac{50}{10} =5 $
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