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=-5Y(Y-2)-Y
We move all terms to the left:
-(-5Y(Y-2)-Y)=0
We calculate terms in parentheses: -(-5Y(Y-2)-Y), so:We get rid of parentheses
-5Y(Y-2)-Y
We add all the numbers together, and all the variables
-1Y-5Y(Y-2)
We multiply parentheses
-5Y^2-1Y+10Y
We add all the numbers together, and all the variables
-5Y^2+9Y
Back to the equation:
-(-5Y^2+9Y)
5Y^2-9Y=0
a = 5; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·5·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*5}=\frac{0}{10} =0 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*5}=\frac{18}{10} =1+4/5 $
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