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=0.5Y^2-1
We move all terms to the left:
-(0.5Y^2-1)=0
We get rid of parentheses
-0.5Y^2+1=0
a = -0.5; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-0.5)·1
Δ = 2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2}}{2*-0.5}=\frac{0-\sqrt{2}}{-1} =-\frac{\sqrt{}}{-1} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2}}{2*-0.5}=\frac{0+\sqrt{2}}{-1} =\frac{\sqrt{}}{-1} $
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