Y=1/2(x-3)(x+1)

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Solution for Y=1/2(x-3)(x+1) equation: 



=1/2(Y-3)(Y+1)

We move all terms to the left:

-(1/2(Y-3)(Y+1))=0



Domain of the equation: 2(Y-3)(Y+1))!=0

Y∈R



We multiply parentheses ..

-(1/2(+Y^2+Y-3Y-3))=0

We multiply all the terms by the denominator


-(1=0

We add all the numbers together, and all the variables

=0

Y=0/1

Y=0

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