Y=1/3(3y+6)+10

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Solution for Y=1/3(3y+6)+10 equation: 


x in (-oo:+oo)

Y = (1/3)*(3*y+6)+10 // - (1/3)*(3*y+6)+10

Y-((1/3)*(3*y+6))-10 = 0

(-1/3)*(3*y+6)+Y-10 = 0

Y-1/3*(3*y+6)-10 = 0

Y-1/3*(3*y+6)-10 = 0

Y-y-10-2 = 0

Y-y-12 = 0

Y-y-12 = 0

x belongs to the empty set

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