If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=100Y-5Y^2
We move all terms to the left:
-(100Y-5Y^2)=0
We get rid of parentheses
5Y^2-100Y=0
a = 5; b = -100; c = 0;
Δ = b2-4ac
Δ = -1002-4·5·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-100}{2*5}=\frac{0}{10} =0 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+100}{2*5}=\frac{200}{10} =20 $
| 6+3y=8y-14. | | 3t+12=21 | | 18+4x÷10=18.4x | | (51-7x)x3=27 | | C=11+8=x | | 2^2x-1=10 | | (a)5 | | B(x)=40.75-0.07x | | (3x-11)/4-(3-5x)/8=(x+6)/2 | | 12+33x=45x | | -6=½k | | 2p=p+4/9p= | | .3x^2+.8x-2=0 | | 5/2x+11-4=21 | | 4x-20=4x+50 | | 78.50(x)+12=404.50 | | (2x^2-9x+3)/(x-3)=0 | | (2x^2-9x+3)/(x-3)=x | | 0=2x/(3x/40) | | 11.c=88 | | 2.6=1.2-0.4y | | (60)=x/160 | | 5-8x-2x=-15 | | (4x+10)x=90 | | 5(10^(x+2))=60 | | (8x)=(21x-12)=(10x+9) | | 0.7+3b=1 | | 36x−4=1216 | | 1.4x-3.8=7(x+4)-38 | | F(x)^-1=2x^2-8x+3 | | x-2-4x=7 | | 4x(-5)=-20x |