Y=2(x+1)=2(3+1)=

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Solution for Y=2(x+1)=2(3+1)= equation: 



=2(Y+1)=2(3+1)=

We move all terms to the left:

-(2(Y+1))=0



We calculate terms in parentheses: -(2(Y+1)), so:

2(Y+1)

We multiply parentheses

2Y+2

Back to the equation:

-(2Y+2)



We get rid of parentheses

-2Y-2=0

We move all terms containing Y to the left, all other terms to the right

-2Y=2

Y=2/-2

Y=-1

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