Y=20x+x2

Solution for Y=20x+x2 equation:

=20Y+Y2

We move all terms to the left:

-(20Y+Y2)=0

We add all the numbers together, and all the variables

-(+20Y+Y^2)=0

We get rid of parentheses

-Y^2-20Y=0

We add all the numbers together, and all the variables

-1Y^2-20Y=0

a = -1; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·(-1)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*-1}=\frac{0}{-2}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*-1}=\frac{40}{-2}
=-20
$