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=2Y+6Y^2
We move all terms to the left:
-(2Y+6Y^2)=0
We get rid of parentheses
-6Y^2-2Y=0
a = -6; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-6)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-6}=\frac{0}{-12} =0 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-6}=\frac{4}{-12} =-1/3 $
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