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=2Y-3/Y+1
We move all terms to the left:
-(2Y-3/Y+1)=0
Domain of the equation: Y+1)!=0We get rid of parentheses
Y∈R
-2Y+3/Y-1=0
We multiply all the terms by the denominator
-2Y*Y-1*Y+3=0
We add all the numbers together, and all the variables
-1Y-2Y*Y+3=0
Wy multiply elements
-2Y^2-1Y+3=0
a = -2; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·(-2)·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5}{2*-2}=\frac{-4}{-4} =1 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5}{2*-2}=\frac{6}{-4} =-1+1/2 $
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