If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=2Y^2
We move all terms to the left:
-(2Y^2)=0
a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$Y=\frac{-b}{2a}=\frac{0}{-4}=0$
| (4)(2^(2x))-(5)(2^(x))+1=0 | | 4+2a=18 | | 31+116+m1=180 | | 5(x-20)=300 | | 2y+9=5y+20 | | 4u+5=-11 | | 49x^2+48=98x | | y/5+12=29 | | 5/x-9=3 | | 87=4x+11 | | 3(2x-15)=1 | | y/9=13/7 | | 6=9x=20+2x | | 17–3v=2 | | 5x+4=31=2x | | 5b3=17 | | x=18015 | | 6.z+28=64 | | 2x+17=65-4x | | 15.b+30=60 | | 2.b+35=53 | | 9x-(3x+7)=7x-38 | | -3(x-4)=12-9x | | 0.05y+y=30 | | 9c-4=5(c+4) | | 35+4y-10=14y-11-4y | | 8(3w+4)/3=0 | | -13x-20=10x/70 | | 8y+14=110 | | x-20=-10x/70 | | 11y+5=115 | | 11y+5=65 |