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=2Y^2+3
We move all terms to the left:
-(2Y^2+3)=0
We get rid of parentheses
-2Y^2-3=0
a = -2; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-2)·(-3)
Δ = -24
Delta is less than zero, so there is no solution for the equation
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