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=3(Y*Y)-12Y+13
We move all terms to the left:
-(3(Y*Y)-12Y+13)=0
We add all the numbers together, and all the variables
-(3(+Y*Y)-12Y+13)=0
We calculate terms in parentheses: -(3(+Y*Y)-12Y+13), so:We get rid of parentheses
3(+Y*Y)-12Y+13
We add all the numbers together, and all the variables
-12Y+3(+Y*Y)+13
We multiply parentheses
3Y^2-12Y+13
Back to the equation:
-(3Y^2-12Y+13)
-3Y^2+12Y-13=0
a = -3; b = 12; c = -13;
Δ = b2-4ac
Δ = 122-4·(-3)·(-13)
Δ = -12
Delta is less than zero, so there is no solution for the equation
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