Y=3(x+2)+x

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Solution for Y=3(x+2)+x equation: 



=3(Y+2)+Y

We move all terms to the left:

-(3(Y+2)+Y)=0



We calculate terms in parentheses: -(3(Y+2)+Y), so:

3(Y+2)+Y

We add all the numbers together, and all the variables

Y+3(Y+2)

We multiply parentheses

Y+3Y+6

We add all the numbers together, and all the variables

4Y+6

Back to the equation:

-(4Y+6)



We get rid of parentheses

-4Y-6=0

We move all terms containing Y to the left, all other terms to the right

-4Y=6

Y=6/-4

Y=-1+1/2

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