Y=3/5u+;u

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Solution for Y=3/5u+;u equation: 



=3/5Y+Y

We move all terms to the left:

-(3/5Y+Y)=0



Domain of the equation: 5Y+Y)!=0

Y∈R



We add all the numbers together, and all the variables

-(+Y+3/5Y)=0

We get rid of parentheses

-Y-3/5Y=0

We multiply all the terms by the denominator


-Y*5Y-3=0

Wy multiply elements

-5Y^2-3=0

a = -5; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-5)·(-3)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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