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=3Y(1/2)Y-2+1
We move all terms to the left:
-(3Y(1/2)Y-2+1)=0
Domain of the equation: 2)Y-2+1)!=0We add all the numbers together, and all the variables
Y!=0/1
Y!=0
Y∈R
-(3Y(+1/2)Y-2+1)=0
We multiply all the terms by the denominator
-(3Y(+1=0
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