Y=3x+(30-40)

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Solution for Y=3x+(30-40) equation: 



=3Y+(30-40)

We move all terms to the left:

-(3Y+(30-40))=0

We add all the numbers together, and all the variables

-(3Y+(-10))=0



We calculate terms in parentheses: -(3Y+(-10)), so:

3Y+(-10)

We add all the numbers together, and all the variables

3Y-10

Back to the equation:

-(3Y-10)



We get rid of parentheses

-3Y+10=0

We move all terms containing Y to the left, all other terms to the right

-3Y=-10

Y=-10/-3

Y=3+1/3

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