Y=4(x+5)-2(x+1)2

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Solution for Y=4(x+5)-2(x+1)2 equation: 



=4(Y+5)-2(Y+1)2

We move all terms to the left:

-(4(Y+5)-2(Y+1)2)=0



We calculate terms in parentheses: -(4(Y+5)-2(Y+1)2), so:

4(Y+5)-2(Y+1)2

We multiply parentheses

4Y-4Y+20-4

We add all the numbers together, and all the variables

16

Back to the equation:

-(16)



We move all terms containing Y to the left, all other terms to the right

=16

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