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=4(Y+8)(Y-6)
We move all terms to the left:
-(4(Y+8)(Y-6))=0
We multiply parentheses ..
-(4(+Y^2-6Y+8Y-48))=0
We calculate terms in parentheses: -(4(+Y^2-6Y+8Y-48)), so:We get rid of parentheses
4(+Y^2-6Y+8Y-48)
We multiply parentheses
4Y^2-24Y+32Y-192
We add all the numbers together, and all the variables
4Y^2+8Y-192
Back to the equation:
-(4Y^2+8Y-192)
-4Y^2-8Y+192=0
a = -4; b = -8; c = +192;
Δ = b2-4ac
Δ = -82-4·(-4)·192
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-56}{2*-4}=\frac{-48}{-8} =+6 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+56}{2*-4}=\frac{64}{-8} =-8 $
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