Y=4x2+20

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Solution for Y=4x2+20 equation: 



=4Y^2+20

We move all terms to the left:

-(4Y^2+20)=0

We get rid of parentheses

-4Y^2-20=0

a = -4; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·(-4)·(-20)
Δ = -320
Delta is less than zero, so there is no solution for the equation

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