Y=4x2+8x+0

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Solution for Y=4x2+8x+0 equation:



=4Y^2+8Y+0
We move all terms to the left:
-(4Y^2+8Y+0)=0
We get rid of parentheses
-4Y^2-8Y-0=0
We add all the numbers together, and all the variables
-4Y^2-8Y=0
a = -4; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-4)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-4}=\frac{0}{-8} =0 $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-4}=\frac{16}{-8} =-2 $

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