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=4Y^2-15Y-10
We move all terms to the left:
-(4Y^2-15Y-10)=0
We get rid of parentheses
-4Y^2+15Y+10=0
a = -4; b = 15; c = +10;
Δ = b2-4ac
Δ = 152-4·(-4)·10
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{385}}{2*-4}=\frac{-15-\sqrt{385}}{-8} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{385}}{2*-4}=\frac{-15+\sqrt{385}}{-8} $
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