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=4Y^2-256
We move all terms to the left:
-(4Y^2-256)=0
We get rid of parentheses
-4Y^2+256=0
a = -4; b = 0; c = +256;
Δ = b2-4ac
Δ = 02-4·(-4)·256
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*-4}=\frac{-64}{-8} =+8 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*-4}=\frac{64}{-8} =-8 $
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