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=4Y^2-4Y-24
We move all terms to the left:
-(4Y^2-4Y-24)=0
We get rid of parentheses
-4Y^2+4Y+24=0
a = -4; b = 4; c = +24;
Δ = b2-4ac
Δ = 42-4·(-4)·24
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20}{2*-4}=\frac{-24}{-8} =+3 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20}{2*-4}=\frac{16}{-8} =-2 $
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