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=5/3(Y-2+2
We move all terms to the left:
-(5/3(Y-2+2)=0
Domain of the equation: 3(Y-2+2)!=0We add all the numbers together, and all the variables
Y∈R
-(5/3(+Y)=0
We multiply all the terms by the denominator
-(5=0
We add all the numbers together, and all the variables
=0
Y=0/1
Y=0
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