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=5Y-9(Y)2
We move all terms to the left:
-(5Y-9(Y)2)=0
We add all the numbers together, and all the variables
-(+5Y-9Y^2)=0
We get rid of parentheses
9Y^2-5Y=0
a = 9; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·9·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*9}=\frac{0}{18} =0 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*9}=\frac{10}{18} =5/9 $
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