Y=5x2-10x+1

Solution for Y=5x2-10x+1 equation:

=5Y^2-10Y+1

We move all terms to the left:

-(5Y^2-10Y+1)=0

We get rid of parentheses

-5Y^2+10Y-1=0

a = -5; b = 10; c = -1;
Δ = b2-4ac
Δ = 102-4·(-5)·(-1)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-4\sqrt{5}}{2*-5}=\frac{-10-4\sqrt{5}}{-10}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+4\sqrt{5}}{2*-5}=\frac{-10+4\sqrt{5}}{-10}
$