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=6.1+0.6Y+-0.01Y^2
We move all terms to the left:
-(6.1+0.6Y+-0.01Y^2)=0
We use the square of the difference formula
-(6.1+0.6Y-0.01Y^2)=0
We get rid of parentheses
0.01Y^2-0.6Y-6.1=0
a = 0.01; b = -0.6; c = -6.1;
Δ = b2-4ac
Δ = -0.62-4·0.01·(-6.1)
Δ = 0.604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{0.604}}{2*0.01}=\frac{0.6-\sqrt{0.604}}{0.02} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{0.604}}{2*0.01}=\frac{0.6+\sqrt{0.604}}{0.02} $
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