Y=7x2+8x+C

Solution for Y=7x2+8x+C equation:

=7Y^2+8Y+

We move all terms to the left:

-(7Y^2+8Y+)=0

We get rid of parentheses

-7Y^2-8Y-=0

We add all the numbers together, and all the variables

-7Y^2-8Y=0

a = -7; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-7)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-7}=\frac{0}{-14}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-7}=\frac{16}{-14}
=-1+1/7
$