Y=8x2-4x+3

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Solution for Y=8x2-4x+3 equation: 



=8Y^2-4Y+3

We move all terms to the left:

-(8Y^2-4Y+3)=0

We get rid of parentheses

-8Y^2+4Y-3=0

a = -8; b = 4; c = -3;
Δ = b2-4ac
Δ = 42-4·(-8)·(-3)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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