Y=p2+7;p=6

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Solution for Y=p2+7;p=6 equation:



=Y2+7Y=6
We move all terms to the left:
-(Y2+7Y)=0
We add all the numbers together, and all the variables
-(+Y^2+7Y)=0
We get rid of parentheses
-Y^2-7Y=0
We add all the numbers together, and all the variables
-1Y^2-7Y=0
a = -1; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-1)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-1}=\frac{0}{-2} =0 $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-1}=\frac{14}{-2} =-7 $

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