Y=x(2)-4

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Solution for Y=x(2)-4 equation:



=Y(2)-4
We move all terms to the left:
-(Y(2)-4)=0
We add all the numbers together, and all the variables
-(+Y^2-4)=0
We get rid of parentheses
-Y^2+4=0
We add all the numbers together, and all the variables
-1Y^2+4=0
a = -1; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-1)·4
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-1}=\frac{-4}{-2} =+2 $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-1}=\frac{4}{-2} =-2 $

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