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=Y(Y+29)
We move all terms to the left:
-(Y(Y+29))=0
We calculate terms in parentheses: -(Y(Y+29)), so:We get rid of parentheses
Y(Y+29)
We multiply parentheses
Y^2+29Y
Back to the equation:
-(Y^2+29Y)
-Y^2-29Y=0
We add all the numbers together, and all the variables
-1Y^2-29Y=0
a = -1; b = -29; c = 0;
Δ = b2-4ac
Δ = -292-4·(-1)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-29}{2*-1}=\frac{0}{-2} =0 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+29}{2*-1}=\frac{58}{-2} =-29 $
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