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=Y2+3Y-16
We move all terms to the left:
-(Y2+3Y-16)=0
We add all the numbers together, and all the variables
-(+Y^2+3Y-16)=0
We get rid of parentheses
-Y^2-3Y+16=0
We add all the numbers together, and all the variables
-1Y^2-3Y+16=0
a = -1; b = -3; c = +16;
Δ = b2-4ac
Δ = -32-4·(-1)·16
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{73}}{2*-1}=\frac{3-\sqrt{73}}{-2} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{73}}{2*-1}=\frac{3+\sqrt{73}}{-2} $
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