Y=x2+4x+5

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Solution for Y=x2+4x+5 equation:



=Y2+4Y+5
We move all terms to the left:
-(Y2+4Y+5)=0
We add all the numbers together, and all the variables
-(+Y^2+4Y+5)=0
We get rid of parentheses
-Y^2-4Y-5=0
We add all the numbers together, and all the variables
-1Y^2-4Y-5=0
a = -1; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·(-1)·(-5)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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