Y=x2+4x-16

Solution for Y=x2+4x-16 equation:

=Y2+4Y-16

We move all terms to the left:

-(Y2+4Y-16)=0

We add all the numbers together, and all the variables

-(+Y^2+4Y-16)=0

We get rid of parentheses

-Y^2-4Y+16=0

We add all the numbers together, and all the variables

-1Y^2-4Y+16=0

a = -1; b = -4; c = +16;
Δ = b2-4ac
Δ = -42-4·(-1)·16
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{5}}{2*-1}=\frac{4-4\sqrt{5}}{-2}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{5}}{2*-1}=\frac{4+4\sqrt{5}}{-2}
$