Y=x2+5x=4

Solution for Y=x2+5x=4 equation:

=Y2+5Y=4

We move all terms to the left:

-(Y2+5Y)=0

We add all the numbers together, and all the variables

-(+Y^2+5Y)=0

We get rid of parentheses

-Y^2-5Y=0

We add all the numbers together, and all the variables

-1Y^2-5Y=0

a = -1; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-1)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-1}=\frac{0}{-2}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-1}=\frac{10}{-2}
=-5
$