Y=x2-20x+100

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Solution for Y=x2-20x+100 equation: 



=Y2-20Y+100

We move all terms to the left:

-(Y2-20Y+100)=0

We add all the numbers together, and all the variables

-(+Y^2-20Y+100)=0

We get rid of parentheses

-Y^2+20Y-100=0

We add all the numbers together, and all the variables

-1Y^2+20Y-100=0

a = -1; b = 20; c = -100;
Δ = b2-4ac
Δ = 202-4·(-1)·(-100)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{-20}{-2}=+10$

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