Y=x2-2x-48

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Solution for Y=x2-2x-48 equation:



=Y2-2Y-48
We move all terms to the left:
-(Y2-2Y-48)=0
We add all the numbers together, and all the variables
-(+Y^2-2Y-48)=0
We get rid of parentheses
-Y^2+2Y+48=0
We add all the numbers together, and all the variables
-1Y^2+2Y+48=0
a = -1; b = 2; c = +48;
Δ = b2-4ac
Δ = 22-4·(-1)·48
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*-1}=\frac{-16}{-2} =+8 $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*-1}=\frac{12}{-2} =-6 $

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